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Exercise solution:
A variant of number-interval

(define (number-interval f t)
 (cond ((< f t)
         (cons f (number-interval (+ f 1) t)))
       ((> f t )
         (cons f (number-interval (- f 1) t)))
       (else ; (= f t)
         (list f))))

Exercise solution: A variant of number-interval

Exercise solution:
A variant of number-interval