/** Solution to exercise 10.8, p. 355, "C by Dissection"
 *
 *  10. March, 2003. Lone Leth Thomsen
 **/

#include <stdio.h>

int main(int argc, char* argv[])
{
    char* p[2][3] = {{"abc", "defg", "hi"},{"jklmno", "pqrstuvw", "xyz"}};

    printf("%s%c%s","***p                   = ", ***p                    , "\n");     
    printf("%s%c%s","p[0][0][0]             = ", p[0][0][0]              , "\n");     
    printf("%s%c%s","**p[1]                 = ", **p[1]                  , "\n");    
    printf("%s%c%s","p[1][0][0]             = ", p[1][0][0]           , "\n");       
    printf("%s%c%s","**(p[1] + 2)           = ", **(p[1] + 2)            , "\n");    
    printf("%s%c%s","p[1][2][0]             = ", p[1][2][0]            , "\n");     
    //printf("%s%c%s","*(*(p + 1) + 1)[7]   = ", *(*(p + 1) + 1)[7]      , "\n");    
    printf("%s%c%s","(*(*(p + 1) + 1))[7]   = ", (*(*(p + 1) + 1))[7]       , "\n");  
    printf("%s%c%s","p[1][1][7]             = ", p[1][1][7]       , "\n");            
    printf("%s%c%s","*(p[1][2] + 2)         = ", *(p[1][2] + 2)          , "\n");     
    printf("%s%c%s","p[1][2][2]             = ", p[1][2][2]              , "\n");      
						 
return 0;
}