#include <stdlib.h>

double f (double p1, int p2){
  if (p2 == 0)
    return p1 * 2.0;
  else
    return p1 - p2;
}

int main(void){
  int i = 1, j = 5;
  double d = 2.0, e = 6.0;

  printf("The first result is %lf\n", f(e-d, i+j));
  printf("The second result is %lf\n", f(d-e, 0));

  return 0;
}